5月 08, 2008

【解題】Kindergarten Counting Game

@
ACM Volume IV 494 - Kindergarten Counting Game


The Problem

Everybody sit down in a circle. Ok. Listen to me carefully.

``Woooooo, you scwewy wabbit!''

Now, could someone tell me how many words I just said?


Input and Output

Input to your program will consist of a series of lines, each line containing multiple words (at least one). A ``word'' is defined as a consecutive sequence of letters (upper and/or lower case).

Your program should output a word count for each line of input. Each word count should be printed on a separate line.


Sample Input

Meep Meep!
I tot I taw a putty tat.
I did! I did! I did taw a putty tat.
Shsssssssssh ... I am hunting wabbits. Heh Heh Heh Heh ...


Sample Output

2
7
10
9


解題思考

  這一題的重點在於判斷字元是否是英文字母。

  作法是先利用一個 boolean 變數,代表 "是否已讀到一個 Word"。只要碰到非英文字母,且此變數為真時,就代表在此之前的是符合題意的 "Word" ,因此將記錄的總字數遞增。

  只要將這種解題思維釐清,這一題也就迎刃而解了。


參考解答(C++)

#include <iostream>
#include <string>

using namespace std;

int main(void)
{
    string get;
    while (getline(cin, get))
    {
        int n = 0;
        bool word = false;
        for (int i = 0; i < get.size(); i++)
        {
            if ((get[i] >= 'a' && get[i] <= 'z') ||
                (get[i] >= 'A' && get[i] <= 'Z'))
            {
                word = true;
            }
            else if (word)
            {
                word = false;
                n++;
            }
        }

        if (word) { n++; }

        cout << n << endl;
    }

#ifndef ONLINE_JUDGE
    system("pause");
#endif

    return 0;
}

2 回覆:

kgame 提到...

如果句尾也是英文字,而非標點符號
這份參考解答好像會少算1個的樣子

另外最近在研究字串樣是規則運算式(Ragex)
1行就解決了XD,感覺有點白目
http://kgame-blog.spaces.live.com/blog/cns!1A7962FEA74AB4CB!382.entry
見第2個參考解答

小參 提到...

感謝指正, 已修正

如果照你的 RegExp 解法
用 C 的 scanf() 也可以解喔XD

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